10x^2-32x+28=-2x+x^2+4

Solution for 10x^2-32x+28=-2x+x^2+4 equation:

10x^2-32x+28=-2x+x^2+4

We move all terms to the left:

10x^2-32x+28-(-2x+x^2+4)=0

We get rid of parentheses

10x^2-x^2+2x-32x-4+28=0

We add all the numbers together, and all the variables

9x^2-30x+24=0

a = 9; b = -30; c = +24;
Δ = b2-4ac
Δ = -302-4·9·24
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6}{2*9}=\frac{24}{18}
=1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6}{2*9}=\frac{36}{18}
=2
$